1 row where screengroup = 633

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2009518 - Dentalmedizin, Hamburg 39 - all screens 633 10005048 - 2009518-1 10005048

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CREATE TABLE screengroup_screens (
	screengroup INTEGER NOT NULL, 
	screen VARCHAR(8) NOT NULL, 
	PRIMARY KEY (screengroup, screen), 
	FOREIGN KEY(screengroup) REFERENCES screengroup (id), 
	FOREIGN KEY(screen) REFERENCES screen (id)
);